What is the equation in slope intercept form of the line that passes through the point (-4,47) and (2,-16)

Question

asked Jan 28, 2019 162k views

2 Answers

RanRag · Answer 1 · 2019-02-02T13:41:19+0000

The slope-intercept form:

y=mx+b

The formula of a slope:

m=(y_2-y_1)/(x_2-x_1)

We have the points (-4, 47) and (2, -16). Substitute:

m=(-16-47)/(2-(-4))=(-63)/(6)=-(63:3)/(6:3)=-(21)/(2)

Therefore we have:

y=-(21)/(2)x+b

Put the coordinates of the point (2, -16) to the equation:

$-16=-(21)/(2)(2)+b\\\\-16=-21+b\qquad\text{add 21 from both sides}\\\\5=b\to b=5$

Answer:
$\boxed{y=-(21)/(2)x+5}$