Question

HELP PLEASE ASAP!!!! 20 POINTS!!!!

Answer 1

`\text{The formula of a midpoint:}\\\\\left((x_1+x_2)/(2);\ (y_1+y_2)/(2)\right)\\\\\text{We have}\ R(-2b,\ 2c)\ \text{and}\ T(-2a,\ 0).\ \text{Substitute:}\\\\x=(-2b+(-2a))/(2)=(-2b)/(2)+(-2a)/(2)=-b-a\\\\y=(2c+0)/(2)=(2c)/(2)=c\\\\Answer:\ \boxed{b.\ (-a-b,\ c)}`