Final answer:
To solve this problem, we can set up a system of equations. Using the information given, we can find the current ages of Mrs. Bee and her son.
Step-by-step explanation:
To solve this problem, we can let Mrs. Bee's age be represented by the variable 'B' and her son's age be represented by the variable 'S'.
From the information given, we know that Mrs. Bee's age is six years more than four times her son's age, so we can write the equation: B = 4S + 6.
We also know that three years ago, Mrs. Bee was seven times as old as her son was then, which can be written as: B - 3 = 7(S - 3).
Now, we can solve this system of equations to find the values of B and S.
Substituting the value of B from the first equation into the second equation, we get (4S + 6) - 3 = 7(S - 3). Simplifying this equation gives us 4S + 3 = 7S - 21. Subtracting 4S from both sides gives us 3 = 3S - 21. Adding 21 to both sides, we get 24 = 3S. Dividing both sides by 3, we find that S = 8.
Substituting this value of S back into the first equation, we get B = 4(8) + 6 = 38.
Therefore, Mrs. Bee is currently 38 years old and her son is currently 8 years old.