Answer is: C6H10O4 is correct!
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The molecular formula of this compound is C6H10O4.
Molar mass of empirical; C3H5O2 = 12x3 + 5x1 + 2x16 = 36 + 5 + 32 = 73
Empiricals in the molecular; 146.1/73 = 2
Thus = C6H10O4
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