Answer:
Perimeter = 14 + 2sqrt(17)
Area =28
Explanation:
FG = 8 counted
EH = 6 counted
using the pythagorean theorem
height = 4 and the base = 1 in the right triangle
HG^2 = 4^2 + 1 ^2
hg^2 = 16+1
hg^2= 17
hg= sqrt(17)
ef^2 = 4^2 + 1 ^2
ef^2 = 16+1
ef^2= 17
ef=sqrt(17)
Perimeter = EF+FG + GH+HE
sqrt(17)+ 8+ sqrt(17) + 6
14 + 2sqrt(17)
A =1/2 (b1+b2) * h
b1 =EH b2 = FG and h = 4 height that we used in the perimeter
= 1/2 (6+8) * 4
= 1/2 * 14*4
=28