Question

the perimeter of a rectangle is twice the sum of its length and it’s width. the perimeter is 40 meters and is 2 meters more than twice it’s width

Answer 1

I assume you are looking for the length and width of the rectangle?

W = 6 meters L = 14 meters

Explanation:

P= 2(l + w)

We are given that the length is 2 meters more than double the width.

Let width = x

Let length = 2x + 2

Calculate P based on these.

2 [2x + 2 + x]

2 [3x + 2]

6x + 4 = P

Substitue 40 for P

6x + 4 = 40

6x = 36

x = 6

Substitute 6 in for x in the length and width formulas.

W = 6

L = 14

Check

6 + 14 = 20

And 20 times 2 = 40 meters.