Question

What is the volume of 0.200 mol of an ideal gas at 200. kPa and 400. K?

Answer 1

The ideal gas under STP is 22.4 L/mol. While the gas has a rule of P1V1/T1=P2V2/T2. So the volume under 101 kPa and 273 K is 0.2*22.4=4.48 L.

Answer 2

Answer: The volume of ideal gas is 3.32 L

Step-by-step explanation:

To calculate the volume, we use the equation given by ideal gas equation:

`PV=nRT`

where,

P = pressure of the gas = 200 kPa

V = Volume of gas = ?

n = number of moles of gas = 0.200 moles

R = Gas constant =
`8.31\text{L kPa }mol^(-1)K^(-1)`

T = temperature of the gas = 400 K

Putting values in above equation, we get:

`200kPa* V=0.200mol* 8.31\text{L kPa }mol^(-1)K^(-1)* 400K\\\\V=(0.200* 8.31* 400)/(200)=3.32L`

Hence, the volume of ideal gas is 3.32 L