Dimensions of the rectangle are 25 inches × 17 inches.
Explanation:
Let the length of the rectangle = l inches and width = w inches
The length of the rectangle is 9 inches less than twice the width.
Therefore, l = (2w - 9)
Perimeter of the rectangle is = 84 inches
And perimeter of the rectangle = 2(Length + width)
= 2(l + w)
= 2[(2w - 9) + w]
= 2[3w - 9]
Now 84 = 2{3w - 9)
3w - 9 = \frac{84}{2}
2
84
3w - 9 = 42
3w - 9 = 423w = 42 + 9
3w - 9 = 423w = 42 + 93w = 51
3w - 9 = 423w = 42 + 93w = 51w = \frac{51}{3}
3w - 9 = 423w = 42 + 93w = 51w = \frac{51}{3} 3
3w - 9 = 423w = 42 + 93w = 51w = \frac{51}{3} 351
3w - 9 = 423w = 42 + 93w = 51w = \frac{51}{3} 351
3w - 9 = 423w = 42 + 93w = 51w = \frac{51}{3} 351
w = 17 inches
Since l = 2w - 9
l = 2×17 - 9
= 34 - 9
= 25 inches
Therefore, dimensions of the rectangle are 25 inches × 17 inches.