Question

Using hooke's law find the elastic constant of a spring that stretches 2 cm when 4newton force is applied to it

Answer 1

2N/cm

Explanation:

According to the Hooke's Law, the force required to extend or compress a spring is directly proportional distance you can stretch it, which is represented as:

`F=kx`

where,
`F` is the force which is stretching or compressing the spring,

`k` is the spring constant; and

`x` is the distance the spring is stretched.

Substituting the given values to find the elastic constant
`k` to get:

`F=kx`

`4=k(2)`

`k=(4)/(2)`

`k=2`

Therefore, the elastic constant is 2 Newton/cm.