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What is the perimeter of parallelogram HIJK? Round to the nearest hundredth.

What is the perimeter of parallelogram HIJK? Round to the nearest hundredth.-example-1
User Dan Nagle
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1 Answer

6 votes

Answer:

Perimeter of the parallelogram = 26.64 units

Explanation:

The perimeter of parallelogram = 2(a + b)

Here a = KJ = 7 units.

b = HK

We need to find the HK using the distance formula.

Distance formula =
√((x2 - x1)^2 + (y2 - y1)^2)

H = (-4, 3) and k = (-2, -3)

Now plug in x1 = -4, y1 =3, x2 = -2, y2 = -3 in the distance formula

HK =
√((-2 -(-4))^2 + (-3 - 3)^2)

=
√((-2 +4)^2 + (-6)^2)

=
√(4 + 36)

=
√(40)

HK = b = 6.32 units

Now plug in a = 7 and b = 6.32 in the perimeter formula, we get

Perimeter = 2(7 + 6.32)

= 2(13.32)

= 26.64 units

Thank you.

User Kylekeesling
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8.0k points