Question

in the equation x+3y=6, suppose the x-intercept was at (m,0) and the y- intercept was at the ordered pair (0,n). what is the value of m+n

Answer 1

8

Explanation:

The x intercept is when y = 0

x + 3(0) = 6

x = 6

So (6,0) and m = 6

the y intercept is when x = 0

0 + 3y = 6 Divide by 3

y = 6/3

y = 2

the y intercept is (0,2) and n = 2

Answer

m + n = 6 + 2 = 8