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If the equation of the line y = -5x + 8 is changed to y = -125x + 8, how does the graph change?

2 Answers

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The original line . . . Y = -5x + 8

-- The slope of the line is -5 . It slopes down, 5 steps down for every step forward.

-- The y-intercept is 8 . The line crosses the y-axis at the point where y=8 .

= = = = =

The new line . . . Y = -125x + 8

-- The slope of the line is -125 . It slopes down, 125 steps down for every step forward. That's 25 times as steep as the original line.

-- The y-intercept is 8 . The line crosses the y-axis at the point where y=8 . That's the same as the original line.

User Stian
by
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3 votes

Answer:

A) line is closer to vertical

Explanation:

line is closer to vertical

y = mx + b

If the slope (m) is negative the line slants down. As the slope decreases, the down slant of the line gets steeper and closer to vertical.

User DraganS
by
7.8k points

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