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The block in the illustration is floating in water. Water has a density of 1.0 g/cm 3 and about 30 percent of the block is below water. What is a good estimate of the density of the block?

User Thekevshow
by
8.1k points

2 Answers

4 votes

Answer:

that's true

Step-by-step explanation:

User Andy Jazz
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8.2k points
6 votes

Answer: The density of the block is estimated to be
0.30 g/cm^3.

Step-by-step explanation:

Density of the water,
\rho_w=1.0 g/cm^3

Buoyant force =
\rho* volume* g

g = gravitational acceleration

volume of the block = v

density of the block =
\rho_o

Weight of the Block = Buoyant force exerted by water


rho_o* v* g=\rho_w* 30\%\text{of volume of block}* g


\rho_o* v* g=\rho_w* 0.30v* g


\rho_o* v* 9.8 m/s^2=1 g/cm^3* 0.30v* 9.8 m/s^2


\rho_o=0.30 g/cm^3

The density of the block is estimated to be
0.30 g/cm^3.