Question

CAN SOMEONE HELP ME SOLVE THIS?! It has something to do with invisible numbers, and I get so confused with these! Thank you so much!

Solve:

X^2 - 6x + 58 = 0

Answer 1

Please didixixidi gifjf

Answer 2

To solve for x we apply quadratic formula

`x^2 - 6x + 58 = 0`

quadratic formula is

`x= (-b+-√(b^2-4ac))/(2a)`

From the given equation

a=1 , b=-6 and c= 58

Plug in all the values in the formula

`x= (-(-6)+-√((-6)^2-4(1)(58)))/(2(1))`

`x= (6+-√(-196))/(2)`

square root (-1) is 'i'

`x= (6+-14i)/(2)`

We will get two values for x

`x= (6+14i)/(2)=3+7i`

`x= (6-14i)/(2)=3-7i`

So x= 3+7i , x= 3-7i