99.1k views
3 votes
A car is capable of accelerating at a uniform rate of 0.85 m/s^2. What is the magnitude of the car's displacement if it accelerates from 23.06 m/s to 26.1 m/s?

1 Answer

3 votes

Answer: 87.9 m

Step-by-step explanation:

We can solve the problem by using the following SUVAT equation:


v^2 -u^2 = 2ad

where

v = 26.1 m/s is the final velocity of the car

u = 23.06 m/s is the initial velocity of the car

a = 0.85 m/s^2 is the acceleration of the car

d is the displacement

By re-arranging the equation and substituting the numbers, we find the displacement:


d=(v^2-u^2)/(2a)=((26.1 m/s)^2-(23.06 m/s)^2)/(2(0.85 m/s^2))=87.9 m

User MeLight
by
8.5k points

No related questions found