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8 votes
8 votes
PLEASE HELP ME AND EXPLAIN!!!
Subject: Law of Cosines

PLEASE HELP ME AND EXPLAIN!!! Subject: Law of Cosines-example-1
User Stijn Sanders
by
3.0k points

2 Answers

7 votes
7 votes

Answer:

Explanation:

just plug the numbers in to get your answer. c=90

a=55, b=50. so basically

(90)^2=(55)^2+(50)^2-2(55)(50)*cos90

User Noririco
by
3.1k points
8 votes
8 votes

Answer:

32.7°

Explanation:

Cosine rule


c^2=a^2+b^2-2ab \cos C

Where:

  • a, b and c are the sides of a triangle.
  • C is the angle opposite side c.

From inspection of the given triangle:

  • C = Y
  • c = XZ = 55 ft
  • a = XY = 50 ft
  • b = YZ = 90 ft

Substitute the given values into the formula and solve for Y:


\begin{aligned}c^2 & =a^2+b^2-2ab \cos C\\\implies 55^2 & = 50^2+90^2-2(50)(90) \cos Y\\3025 & = 2500+8100-9000 \cos Y\\9000 \cos Y & = 2500+8100-3025\\9000 \cos Y & =7575\\\cos Y & =(7575)/(9000)\\\cos Y & =(101)/(120)\\Y & =\cos^(-1) \left((101)/(120)\right)\\Y & = 32.68346376^(\circ)\\Y & = 32.7^(\circ) \; \sf (nearest \: tenth)\end{aligned}

User DarLom
by
2.7k points
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