let's do 1, 5, 6, 10 and 13.
1)
well, the denominator is the same on each, so we simply have to look at the numerator, who is larger 3 or 5? 3 < 5, 3 is less than 5, so then........

5)

6)
we can make both denominators the same if we simply multiply each fraction by the other's denominator.

10)
we'll convert the mixed fractions to improper fractions first, then make their denominator the same just like we did in 6).
![\bf \stackrel{mixed}{4(1)/(7)}\implies \cfrac{4\cdot 7+1}{7}\implies \stackrel{improper}{\cfrac{29}{7}}~\hfill \stackrel{mixed}{3(3)/(18)}\implies \cfrac{3\cdot 18+3}{18}\implies \stackrel{improper}{\cfrac{57}{18}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} \cfrac{29}{7}\cdot \cfrac{18}{18}\implies \cfrac{522}{126} \\\\\\ \cfrac{57}{18}\cdot \cfrac{7}{7}\implies \cfrac{399}{126} \end{cases}\qquad \implies \cfrac{522}{126}>\cfrac{399}{126}\qquad therefore\qquad 4(1)/(7)>3(3)/(18)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/10qdycpklis469ra9q628y24skhcf7jkho.png)
13)
so both fractions are at a value from 9, so we can simply say, which is larger 2/6 or 4/12?
