Question

Can someone help me please!!!

Let N be the least postive integer whose digits sum to 2018. Compute the sum of the digits of N+1.

Answer 1

Answer: 3

Step-by-step explanation:

Since we want the least number of integers, divide by the largest integer (9).

2018 ÷ 9 = 224 remainder 2

So, N = 2999...999 (there are 224 of the 9's)

Thus, N + 1 = 2999...999 + 1 (there are 224 of the 9's)

= 3000...000 (there are 224 of the 0's)

The sum of the digits is: 3 + 0 + ... + 0 (there are 224 of the 0's)

= 3