Question

I know how to do this and the teacher don't teach it right so I don't get how to do it at all

Answer 1

I dont have time to do all of these right now my apolgies but Ill explain how to do it.

The 3 angles of a triangle add up to 180.

So let me show you how to do 1.
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1. 58 degrees

92, 30, ?

If we add together the first two angles,
92+30= 122
Knowing the total addition of all three angles would ne 180, we can subtract 122 from it to get the third angle.
180-122= 58

So we now know the last angle is 58 degrees because

92+30+58=180

Answer 2

Note that the sum of a triangle's interior angles = 180°

1. 92 + 30 + ∠1 = 180

122 + ∠1 = 180

122 (-122) + ∠1 = 180 (-122)

∠1 = 180 - 122

∠1 = 58°

2. 90 + 67 + ∠1 = 180

157 + ∠1 = 180

∠1 + 157 (-157) = 180 (-157)

∠1 = 180 - 157

∠1 = 23°

3. ∠1 + 63 + 70 = 180

∠ 1 + 133 = 180

∠1 + 133 (-133) = 180 (-133)

∠1 = 180 - 133

∠1 = 47°

4. 180 = 3(∠1)

(180)/3 = (3(∠1))/3

∠1 = 180/3

∠1 = 60°

5. ∠1 + 30 + 30 = 180

∠1 + 60 = 180

∠1 + 60 (-60) = 180 (-60)

∠1 = 120°

6. 180 = 60 + 90 + ∠1

180 = 150 + ∠1

∠1 = 180 (-150)

∠1 = 30°

7. ∠1 = 65 + 77 (isolated interior angles)

∠1 = 142°

8. ∠1 = 109 + 136

∠1 = 145°

9. ∠1 = 116 - 81

∠1 = 35°°

10. ∠y = (180 - 32)/2

∠y = 148/2

∠y = 74°

11. ∠2x = (62 + 84)

∠2x = 146

∠x = 146/2

∠x = 73°

12. 180 = y + y + 5 + 125

180 = 2y + 130

180 (-130) = 2y + 130 (-130)

50 = 2y

(50)/2 = (2y)/2

y = 50/2

y = 25°

13. m∠1 = 40. Isosceles triangles state that the two base angles are congruent.

180 - 40 = 140

140/2 = 70

m∠2 & m∠3 = 70°

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