Question

How do I find the value of 16 to the -3/2 power?

Answer 1

Hello!

Step-by-step explanation:

First, used exponent rules.

`a^-^b=(1)/(a^b)`

`(1)/(16^3^/^2)=64`

Then factor by the numbers.

`4^2=16=4^2`

`(4^2)(3)/(2)`

`4^3`

Refine.

`4^3=4*4*4=64`

`=(1)/(64)`

Answer: →
`(1)/(64)`

Hope this helps!

Thanks!

-Charlie