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The dipole moment of hcl is 1.03d. what is the dipole moment of hcl in c⋅m?

User Kimomaru
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1 Answer

3 votes

Answer: Dipole moment
=3.43* 10^(-30) Cm

Explanation: Dipole moment is defined as product of magnitude of the charge and the distance between the charges of equal magnitude and opposite sign is called as dipole moment.


\mu= e* d


\mu=\text{dipole moment}


e=\text{magnitude of charge}


d=\text{distance between the charges}

S.I unit of dipole moment is Debye (D).

Debye was defined as the dipole moment resulting from two charges of opposite sign but an equal magnitude of
10^(-10) stat coulomb (generally called e.s.u. (electrostatic unit) which were separated by 1 angstrom.(1 angstrom
=10^(-8)cm)


1 Debye=10^(-18)\text{esu cm}


1 esu=3.35* 10^(-10)C


1cm=10^(-2) m


1Debye=10^(-18)*3.35* 10^(-10)C* 10^(-2)m


1Debye=3.35* 10^(-30)Cm


1.03Debye=1.03* 3.35* 10^(-30)Cm


=3.43* 10^(-30) Cm


User Amrish
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