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If 21 mL of gas is subjected to a temperature change from 10.0°C to 120°C and a pressure change from 1.0 atm to 15 atm, the new volume is: (Be sure to use the correct number of significant figures.) 1.9 mL 1.0 mL 0.53 mL 440 mL

User Ross W
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2 Answers

6 votes

Answer:

1.9 ml

Step-by-step explanation:

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User Ekin
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2 votes

The new volume is 1.9 ml


calculation

The new volume is calculated using the combined gas equation

that is P1V1/T1 = P2V2/T2 where

P1= 1.0 atm

V1= 21 ml

T1 = 10.0 c into kelvin = 10 + 273 = 283 k

P2 = 15 atm

V2=? Ml

T2 = 120 c into kelvin = 120 +273 = 393 K


make V2 the subject of the formula by multiplying both side by T2/P2

V2=T2P1v1 / P2T1

V2=[(393 k x 1.0 atm x 21 ml) / (15 atm x 283 K)] = 1.9 Ml


User Deepak Oberoi
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