Question

Which situation has the greatest rate of change? Filling a swimming pool with 100 gallons of water in 15 minutes or pumping 12 gallons of gas into your tank in 3 minutes?

Answer 1

Pumping gas into take with greater rate of change.

Explanation:

Rate of change is equal to change in number of gallons per minutes.

Here we have two case

Case 1: Filling swimming pool with 100 gallons of water in 15 minutes.

So, we find how many gallons fill in 1 minutes.

`\text{Rate }=\frac{\text{Number of gallons}}{\text{Total minutes}}`

`\text{Rate }=(100)/(15)\approx 6.67\text{ gallons/min}`

Case 2: Pumping 12 gallons of gas into tank in 3 minutes.

So, we find how many gallons fill in 1 minutes.

`\text{Rate }=\frac{\text{Number of gallons}}{\text{Total minutes}}`

`\text{Rate }=(12)/(3)\Rightarrow 4\text{ gallons/min}`

Rate of case 2 is greater than case 1.

Thus, Pumping gas into tank with greater rate of change.