Question

How many gallons each of 30% alcohol and 5% alcohol should be mixed to obtain 25 gal of 15% alcohol?

Answer 1

See below

Explanation:

x = amount of 30 % alcohol to use total amount of alcohol = .30 x

25-x = amount of 5% alcohol to use total amount of alcohol = .05 (25-x)

total alcohol in ingredients = total alcohol in end product

.30x + .05(25-x) = .15 (25)

.25x + 1.25 = 3.75

x = 10 gal = 30% then 5 % = 25-10 = 15 gal