Answer:
he solution of the quadratic equation is x=-9 and x =2
So (a) and (f) are correct option
Explanation:
We have given the equation
![2x^2+7x=14=x^2+4](https://img.qammunity.org/2019/formulas/mathematics/middle-school/ynfhmgihfssxrjyrb0b2uxhigq28mi15i9.png)
![x^2+7x-18=0](https://img.qammunity.org/2019/formulas/mathematics/middle-school/c95taa2qo7f9rt6wcu1u2c55rvzpe7r0xb.png)
![x^2+9x-2x-18=0](https://img.qammunity.org/2019/formulas/mathematics/middle-school/31r7nldtk0vr217bvovrtwgg3hbs1i997f.png)
![x(x+9)-2(x+9)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/2z0yen97zl6n5h91ry7mp1uau3pud1xa3n.png)
Now taking (x+9) common
![(x+9)(x-2)=0](https://img.qammunity.org/2019/formulas/mathematics/middle-school/mtrfxu92tympx707kajgtvirm6hwwljb7q.png)
x = -9 and x= 2 are the roots of the equation
So the solution of the quadratic equation is x=-9 and x =2
So (a) and (f) are correct option