43.2k views
4 votes
Joe and maxine are playing a game where they flip a fair coin four times and try to predict the outcomes. Maxine thinks that the probability of getting all heads in the four flips is equal to the probability of getting no heads in the four flips. Joe disagrees. He thinks that the probability of getting all heads is greater. The sample space of possible outcomes is listed below. H represents heads t represents tails who is correct Joe or Maxine

User Makc
by
5.6k points

2 Answers

3 votes

Final answer:

The probability of getting all heads in four coin flips is equal to the probability of getting no heads.

Step-by-step explanation:

In this game, Joe and Maxine are flipping a fair coin four times and trying to predict the outcomes. Maxine thinks that the probability of getting all heads in the four flips is equal to the probability of getting no heads in the four flips. Joe disagrees, as he thinks that the probability of getting all heads is greater.

To determine who is correct, we need to calculate the probabilities. The sample space of possible outcomes for flipping a fair coin four times is {HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT, THHH, THHT, THTH, THTT, TTHH, TTHT, TTTH, TTTT}.

There is only one outcome of getting all heads (HHHH) and only one outcome of getting no heads (TTTT). Therefore, the probability of getting all heads is equal to the probability of getting no heads, so Maxine is correct.

User Jfmercer
by
5.1k points
5 votes
h,t,h,h they are both equal portability because you could get eithed
User Tom Pohl
by
5.2k points