Question

Americium-244 has a half-life of 10 hours. If you start with 130 grams of Americium-244, how much would you have remaining after 60 hours have passed?

Answer 1

Answer: 2.03 g

Explanation:

We can calculate the amount of americium-244 left by using the following equation:

`m(t)=m_0 ((1)/(2))^{(t)/(t_(1/2))}`

where

`m_0 = 130 g` is the initial mass of the sample

`t = 60 h` is the time passed

`t_(1/2)` is the half-life

Substituting data into the equation, we find

`m(t)=(130 g)((1)/(2))^{(60 h)/(10 h)}=(130 g)((1)/(2))^6=2.03 g`