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Calculate the molar mass of a gas at 506 torr and 99°c if 206 ng of gas occupies 0.206 ul. (

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PV = nRT

and n = mass / mw

PV = (mass / mw) RT

mw = mass RT / PV

P = 352 torr = 352 torr x (1 atm / 760 torr) = 0.463 atm

V = 0.206x10^-6 L

R = 0.0821 L atm /moleK

T = 45C = 45+273 = 318 K

mass = 243x10^-9 g

mw = (243x10^-9 g)x(0.0821 L atm /moleK)x(318 K) / [(0.463 atm)x(0.206x10^-6 L)]

mw = 66.5 g/mole

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