165k views
2 votes
Quadratic equations and complex numbers PPEASE ANSWER ASAP

Quadratic equations and complex numbers PPEASE ANSWER ASAP-example-1
User TeTeT
by
6.5k points

2 Answers

5 votes

When you solve the following equation, solving for the quadratic formula.

The answer is; x=4

Next time pay attention in class.

Quadratic equations and complex numbers PPEASE ANSWER ASAP-example-1
User Tomas Mikula
by
5.5k points
4 votes

Answer:

12.
x=-3(1)/(2), x = 6

15.
4

Explanation:

12.
2x^2-5x=42

To solve this quadratic equation, we will put all the variables and constants on one side of the equation and factorize it.


2x^2-5x-42=0


2x^2-12x+7x-42=0


2x(x-6)+7(x-6)=0


(2x+7)(x-6)=0


x=-(7)/(2), x = 6


x=-3(1)/(2), x = 6

Therefore, the solutions to the given expression are 3(1/2) and 6.


15.
3x=8+√(3x+4)


3x-8=√(3x+4)

Squaring both the sides to get:


(3x-8)^2=(3x+4)^2


9x^2-48x+64=3x+4


9x^2-51x+60=0


3(3x^2-17x+20)=0


3x^2-17x+20=0


3x^2-12x-5x+20=0


3x(x-4)-5(x-4)=0


x=(3)/(5) (ignore), x=4

Therefore, the solution to the given expression is 4.

User Moses Machua
by
6.5k points