Question

A sample of a gas in a rigid container has an initial pressure of 1.049 kPa and an initial temperature of 7.39 K. The temperature is increased to 30.70 K. What is the new pressure?

Answer 1

Answer:- 4.36 kPa

Solution:- At constant volume, the pressure of the gas is directly proportional to the kelvin temperature.

`(P_1)/(T_1)=(P_2)/(T_2)`

Where the subscripts 1 and 2 are representing initial and final quantities.

From given data:

`P_1` = 1.049 kPa

`P_2` = ?

`T_1` = 7.39 K

`T_2` = 30.70 K

For final pressure, the equation could also be rearranged as:

`P_2=(P_1T_2)/(T_1)`

Let's plug in the values in it:

`P_2=(1.049kPa(30.70K))/(7.39K)`

`P_2` = 4.36 kPa

So, the new pressure of the gas is 4.36 kPa.