Question

A ball is thrown up in the air and then caught 10 seconds later. How high did it go and what was the initial speed up? (6)

Answer 1

high=125m

speed up=50m s-¹

Step-by-step explanation:

consider acceleration due to gravity = 10m s-²

upward as positive

in t=5s

ball rest momentarily velocity=0

you can know this by drawing s-t graph

consider the upward movement t=0-5s

we now have v=0 t=5 a= -10 and need find u

so use a=[v-u]/t

-10=[0-u]/5

-50=-u

u=50 ms-¹

then let find the displacement

s = (v+u)t*1/2

s= 50*5*1/2

s=125m