Question

Five chips numbered 1 through 5 are placed in a bag. A chip is drawn and replaced. Then a second chip is drawn. Find the probability that one chip is even AND the other is odd. (Hint: You can choose an even chip and then an odd chip, or an odd chip and then an even chip.)

Answer 1

There are 3 odd and 2 even numbers involved here.

So Prob( even then odd) = 2/5 * 3/5 = 6/25

Pro(odd then even) = 3/5 * 2/5 = 6/25

Therefore Prob( either of the above) = 6/25 + 6/25 = 12/25 (answer)

Answer 2

1 out of 5, since ther are still 5 chips in the bag
hope thishelps
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