Question

Solve c³-5c²-6c = 0 for c.

Answer 1

c = - 1, c = 0, c = 6

Explanation:

c³ - 5c² - 6c = 0 ← factor out c from each term on the left side

c(c² - 5c - 6) = 0 ← factoring the quadratic

c(c - 6)(c + 1) = 0

equate each factor to zero and solve for c

c = 0

c - 6 = 0 ⇒ c = 6

c + 1 = 0 ⇒ c = - 1