Answer:
238.2 kJ
Step-by-step explanation:
Mass of air = volume * density
= 4 x 4 x 3 x 1 kg/m^3 = 48 kg
Specific heat of air = 993 J /(kg C)
993 = x Joules / ( 48 kg * 5 C) shows x = 238320 j
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