Question

Write the equation of the line that goes through each set of points (-1,6),(3-2)

Answer 1

The point-slope form:

`y-y_1=m(x-x_1)\\\\m=(y_2-y_1)/(x_2-x_1)`

We have the points (-1, 6) and (3, -2). Substitute:

`m=(-2-6)/(3-(-1))=(-8)/(4)=-2\\\\y-6=-2(x-(-1))\\\\y-6=-2(x+1)\qquad\text{use distributive property}\\\\y-6=-2x-2\qquad\text{add 6 to both sides}\\\\y=-2x+4\qquad\text{add 2x to both sides}\\\\2x+y=4`

Answer:

y - 6 = -2(x + 1) point-slope form

y = -2x + 4 slope-intercept form

2x + y = 4 standard form