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28 votes
28 votes
A gas tank has a volume of 28.1 m 3 and a pressure of 18.4 atm. The temperature of the gas is 32ºC. What is the Celsius temperature when the gas is put in an 11.2 m 3 tank with a pressure of 22.7 atm?

User EKanadily
by
3.1k points

1 Answer

20 votes
20 votes
The Combined Gas Law states that
P
1
V
1
T
1
=
P
2
V
2
T
2
.
P
= Pressure
V
= Volume
T
= Temperature
Since we're using a gas tank and it isn't specified, I'm going to assume the Volume remains constant, so we can eliminate the Vs, giving us
P
1
T
1
=
P
2
T
2
.
Plugging in values:
18.4atm
32°C
=
22.7atm
T
2
We need to isolate the
T
2
, so we'll cross multiply and isolate the value.
T
2
18.4atm
=
22.7 atm * 32°C
T
2
=
22.7 atm * 32°C
18.4atm
Now let's simplify the equation. Our atm's cancel, giving us:
T
2
=
22.7 * 32°C
18.4
After calculating the values and applying sig figs (3 sig figs), we are given
39.5°C
User Alex Wood
by
2.8k points