Question

How do I complete a quadratic equation? I am currently doing revision for an exam and can't remember how to complete these (ex:
`4x^(2) - 2x -3 = 0` )

Answer 1

Eqaution = -b+-Sqrt of b^2 - 4ac / 2

-2 become +2 so

2 +-Sqrt 4 - 4(4)(-3) / 2

2 +- Sqrt 52 / 2

2 +- 2 sqrt 13 / 2

divide

1 +- 1 sqrt 13

Answers: 2 sqrt 13 and sqrt 13

Answer 2

The quadratic equation is:

`x = \frac{-b ± \sqrt{b^(2) - 4ac}}{2a}` Ignore the "A", I can't get rid of it.

ax² + bx + c = 0 That's where you find/get a, b, and c

With that example

a= 4

b = -2

c = -3

Now we plug it into the equation

`x=\frac{-(-2)±\sqrt{(-2)^(2)-4(4)(-3)}} {2(4)}  = \frac{2±√(4+48)} {8} =\frac{2±√(52)} {8}` (Again ignore the A)

`x = \frac{2±√(52)} {8} =  \frac{2±2√(13)} {8}`

I think you can factor out the 2

`x = \frac{1±√(13)} {4}`

Your answers:

`x = \frac{1+√(13)} {4}`

`x = \frac{1-√(13)} {4}`