Answer:
1. Coefficient is 1
2. 166
3.
or
![1(2)/(5)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/zn2t3nk8w8cc1clcg19wm8dstpn8gh9bpr.png)
Explanation:
1. Since there is no number mentioned before the term
therefore its coefficient is 1.
![(1ab^2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/dzj5fawu5vk72cid9fm3uzrvmpb1wwpzyu.png)
2.
![4(3 – 7)^2 + 102](https://img.qammunity.org/2019/formulas/mathematics/middle-school/58j0osnrvn37b0v8fxkq3wlyirp16qqjjh.png)
Using the order of operations, we will start by solving in the brackets first to get:
![4(-4)^2+102](https://img.qammunity.org/2019/formulas/mathematics/middle-school/nr8ha1g469hdnfsdb7iut6hlyhhwxu7alv.png)
![4(16)+102](https://img.qammunity.org/2019/formulas/mathematics/middle-school/2jip6lryss6trj7m3lvzf49vqkzz848p8k.png)
![64+102](https://img.qammunity.org/2019/formulas/mathematics/middle-school/iryvzfzz8f2sai5w54lmjau6mccldex2ax.png)
![166](https://img.qammunity.org/2019/formulas/mathematics/middle-school/wbbcpvxoyoqagjmvh8hekmtt2oxayfjsc5.png)
3.
![\sqrt{(45)/(25) }](https://img.qammunity.org/2019/formulas/mathematics/middle-school/vvewpahxoj08akll4hmbthbhspe7tqm40v.png)
SInce both the numerator and the denominator are under the square root so we can write them as:
![\frac{√(49)} √(25)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/iw5a8i9u2kq8o91dn47tvaw2socz0tjob6.png)
![(7)/(5)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/zca9xc47x6ldp104rtaye6ks2094ytchj2.png)
is an improper fraction so we can write it in mixed form as
![1(2)/(5)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/zn2t3nk8w8cc1clcg19wm8dstpn8gh9bpr.png)