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4 votes
Which is the solution set to the inequality (4x-3)(2x-1)&gt=0?

User Cyberpks
by
8.7k points

1 Answer

6 votes

(4x - 3)(2x - 1) ≥ 0

First, find the zeros:

4x - 3 = 0 2x - 1 = 0

x =
(3)/(4) x =
(1)/(2)

Next, plot these points and choose test points on the outside and between the zeros:

←-------0------
(1)/(2)------
(5)/(8)------
(3)/(4)------1------→

Lastly, plug in the test points and look for a positive result (since it is greater than 0).

Test Point 0: [4(0) - 3][2(0) - 1] = ( - )( - ) = + THIS WORKS!

Test Point
(5)/(8): [4(
(5)/(8)) - 3][2(
(5)/(8)) - 1] = ( - )( + ) = - This does NOT work

Test Point 1: [4(1) - 3][2(1) - 1] = ( + )( + ) = + THIS WORKS!

Answer: x ≤
(1)/(2) or x ≥
(3)/(4)

Interval Notation: (-∞,
(1)/(2)] U [
(3)/(4), ∞)

Graph: ←------
(1)/(2)
(3)/(4)--------

User Sidwyn Koh
by
8.5k points