Question

Point B is on line segment \overline{AC} AC . Given AB=3x,AB=3x, BC=4x+8,BC=4x+8, and AC=5x+10,AC=5x+10, determine the numerical length of \overline{AC}. AC .

Answer 1

X = 1

AC = 15

Explanation:

AB + BC = AC

( 3x ) + ( 4x + 8 ) = 7x + 8

Adding AB + BC = AC So adding the like terms of AB and BC will equals the equation of AC.

7x + 8 = 5x + 10

-8

7x = 5x + 2

-5x

2x = 2

/2

x =1

( 5 x 1 ) = 5 + ( 10 ) = 15 AC = 15