Question

What is the average rate of change of the function f(x)=480(0.3)x from x = 1 to x = 5?

Answer 1

aerage rate of change is just the slope from the endpoints of teh interval

ie
`averagerateofchange=slope=(f(5)-f(1))/(5-1)`

assuming you mean
`f(x)=480(0.3)^x`

evalaute f(5) and f(1)

f(5)=480(0.3)^5=1.1664

f(1)=480(0.3)^1=144

average rate of change=(1.1664-144)/(5-1)=-35.7084

the average rate of change of the function on the interval x=1 to x=5 is -35.7084