Question

An arithmetic sequence is defined by the recursive formula t1 = 11, tn = tn - 1 - 13, where n ∈N and n > 1. Which of these is the general term of the sequence?

Answer 1

Tn= 11 - 13(n-1), where n ∈N and n ≥ 1

Explanation:

I took the test, that's the right answer

hope this helps

Answer 2

coolio

`t_1=11`

`t_n=t_(n-1)-13`

so each term is ound by subtracting 13 from the previous term

an aritmetic sequence can be written as

`t_n=t_1+d(n-1)` were

`t_n` is the nth term

`t_1` is the first term

d is common difference, which can also be found by doing
`t_n-t_(n-1)=d`

n=wich term

we know that
`t_1=11` and we can find d

`t_n=t_(n-1)-13`,
`t_n-t_(n-1)=-13=d`

so te general term is
`t_n=11-13(n-1)` which can also be expanded and written as
`t_n=-13n+24`