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A motorcycle moving at a velocity of 20 m/s accelerates uniformly at 2 The velocity of the motorcycle will be ________ m/s after 10 seconds.

Question 4 options:


A. none of the below
B. 42
C. 40
D. 22

User CtrlDot
by
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1 Answer

4 votes

Answer

C. 40 m/s

Explanation

To solve this, we are using the kinematic equation for final velocity:


v_f=v_i+a*t

where


v_f is the final velocity


v_i is the initial velocity


a is the acceleration


t is the time

We know from our a problem that a motorcycle moving at 20 m/s accelerates uniformly 2 m/s^2 for 10 seconds, so
v_i=20(m)/(s),
a=2(m)/(s^2), and
t=10s.

Now we can replace the values


v_f=v_i+a*t


v_f=20(m)/(s) +2(m)/(s^2) *10s


v_f=20(m)/(s) +2(m)/(s) *10


v_f=20(m)/(s) +20(m)/(s)


v_f=40(m)/(s)

We can conclude that the velocity of the motorcycle will be 40 m/s after 10 seconds.

User Simon Katan
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