Question

What is the approximate value of x in the equation below? log5(15)=x+3 –2.523 –1.317 2.880 7.485

Answer 1

The value of x is -1.371(approximate)

b.

Step-by-step explanation:

Answer 2

Option B is correct.

The value of x is -1.371(approximate)

Step-by-step explanation:

Given equation:
`\log_5 15` =x+3

Using logarithmic rule:

`\log_(10) (ab) =\log_(10) a +\log_(10) b`

`\log_b b =1`

We can write
`\log_5 15` as;

`\log_5 15 =\log_5 (5* 3) = \log_5 5 +\log_5 3`

`\log_5 15 = 1 +\log_5 3` [using logarithmic rule]

By graphing calculator the value of
`\log_5 3` = 0.682606194486.

then, we have

`\log_5 15 = 1 +0.682606194486 =1.682606194486`

substitute this value in [1] to solve for x;

`1.682606194486 =x+3`

Subtract 3 from both sides we have,

`1.682606194486-3 =x+3-3`

Simplify:

-1.31739381 =x or

x =-1.317 (approx.)

Therefore, the approximate value of x is : -1.317