Given equation is y=2x+7 and
![(1)/(2)y=x+(7)/(2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/adzg2mtcr0msbraqb0jbkq2x2vmknnrqrq.png)
Let's simplify the 2nd equation
before we can start graph so that calculation will be easy
![(1)/(2)y=x+(7)/(2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/adzg2mtcr0msbraqb0jbkq2x2vmknnrqrq.png)
multiply both sides by 2 to cancel out fractions
![2*(1)/(2)y=2*x+2*(7)/(2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/dmpctp41n9xuftmg0m05lvc7i3gbcegsgy.png)
y=2x+7
which is exactly same as the first equatoin so graph of both will be exactly same and solution will be infinitely many solutions.
y=2x+7 has y-intercept 7 so first point will be (0,7). Slope is 2 so rise 2 unit up then 1 right and graph the new point.