Question

Write the equation in general form of a line with a slope of -1/3 and a y-intercept of 10/3

Answer 1

General form of a line :
`Ax + By + C = 0`

The slope-intercept form:
`y=mx+b`

m - slope

b - y-intercept

We have

a slope
`\to m=-(1)/(3)` and y-intercept
`\to b=(10)/(3)`.

Substitute:

`y=-(1)/(3)x+(10)/(3)` multiply both sides by 3

`3y=-x+10` subtract 3y from both sides

`0=-x-3y+10` change the signs

`\boxed{x+3y-10=0}`