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A player throws a basketball toward a hoop. The basketball follows a parabolic path that can be modeled by the equation y = - 0.125x^2 + 1.84x + 6. If the center of the hoop is located at (12, 10), will the ball pass through the hoop?

User Bheeshmar
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2 Answers

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Answer:

Since
f(12) = 10, the ball is going to pass through the hoop.

Explanation:

We have the following function.


f(x) = -0.125x^(2) + 1.84x + 6.

If the center of the hoop is located at (12, 10), will the ball pass through the hoop?

This is going to happen if
f(12) = 10. We have to apply f(12) in the equation and verify the result. So:


f(x) = -0.125x^(2) + 1.84x + 6.


f(12) = -0.125*12^(2) + 1.84*12 + 6 = 10.

Since
f(12) = 10, the ball is going to pass through the hoop.

User Hindy
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8.5k points
7 votes
  1. in this exercise you must substitute the value of of x = 12 in the equation of the parable given, if the result is 10 then the ball pass through the hoop
  2. Y = (-.125)(12)^2+ (1.84)(12)+6 = -18+22.08+6 = 10.06≅10 , of this form it is demonstrated, that the ball pass through the hoop
User Nunofmendes
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