Question

PLEASE HELP!!!!!!

Prove that the sum of the measures of the interior angles of a triangle is 180°. Be sure to create and name the appropriate geometric figures.

Answer 1

You can use the Pythagorean theorem for this. A² + B² = C².

You can use this picture to get the proof.

Answer 2

Explanation:

Let∠CBA,∠BAC and ∠BCA be the interior angles of the triangle ABC and Suppose that m || CB as m is the straight line, therefore using the straight line property, we have

∠CAY+∠CAB+∠BAX=180° (1)

Since, m is parallel to BC and AB is transversal, thus

∠BAX=∠CBA(Alternate interior angles of parallel lines cut by a transversal are congruent)

and ∠CAY=∠BCA(Alternate interior angles of parallel lines cut by a transversal are congruent.)

Now, substituting the values of ∠BAX and ∠CAY in equation (1), we have

∠CBA + ∠BAC + ∠BCA = 180°.

Hence, the sum of the measures of the interior angles of a triangle is 180°.