Question

A sample of seawater from a tidal estuary was found to contain a concentration of 825 mg of chloride ion per kg of seawater. If the density of the sample was 1.035 g/mL, what is the molarity of the chloride ion?

Answer 1

The molarity of the chloride ion in the seawater sample is 0.0232 M.

Step-by-step explanation:

To find the molarity of chloride ion in the seawater sample, we need to convert the given concentration from mg/kg to moles per liter.

First, convert the concentration to grams per liter: 825 mg/kg = 0.825 g/L

Next, calculate the moles of chloride ion: moles = mass/molar mass = 0.825 g / (35.45 g/mol) = 0.0232 mol

Finally, divide the moles of chloride ion by the volume of the solution in liters: molarity = 0.0232 mol / 1 L = 0.0232 M