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The length of a rectangular-shaped deck 5 meters longer than its width. If the area of the deck is 66^2 what is the length in meters?

A. 6
B. 11
C. 14.
D. 19

User LEO CHEN
by
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1 Answer

1 vote

The answer is: B. 11

Step-by-step explanation:

1. The area of a rectangle is:


A=LW

Where
L is the length and
W is the width.

2. The length of the rectangular-shaped deck is 5 meters longer than its width, therefore:


L=W+5

3. You must substitute this into
A=LW:


66=(W+5)W\\W^(2)+5W-66=0

4. Now you must solve for the width. You can use the Quadratic formula, which is:


W=\frac{-b+/-\sqrt{b^(2)-4ac}}{2a}

Where:


a=1\\b=5\\c=-66

5. Subsitute values:


W=\frac{-5+/-\sqrt{5^(2)-4(1)(-66)}}{2(1)}\\W=6

6. Then, the lenght is:


L=6m+5m\\L=11m

User ADM
by
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